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The acceleration of10 kg block when F = 30 N , |
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Answer» `2 m// s^(2)`  Common ACCELERATION  `a_(C) = (F)/(M_(1) + M_(2)) = (30)/(15) = 2m//sec^(2)` `f_(2) - f_(1) = 5 xx a` as `"" f_(2) - f_(1) = 35 Ngt f_("required")` [`f_("required")` to have common acceleration = 10 N] |
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