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The acceleration versus time graph of a particle moving in a straight line is show in. The velocity-time graph of the particle would be .A. `A straight lineB. A parabolaC. A circleD. An ellipse

Answer» Correct Answer - B
`a=-(4)/(2) t+4 rArr a=-2t+4`
`v=int a dt+C =int (-2t +4) dt + C=- t^(2) +4t+C`
Hence, graph will be parablic.


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