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The activation energy for the reaction 2H1-→ H2 + 12 is209.5kj/m at 581k. Calculate the fraction of molecules ofreactants having energy equal to a greater than activationenergy. |
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Answer» Activation energy, Ea= 209.5 kJ mol−1Multiply by 1000 to convert in jEa= 209500 J mol−1Temperature, T = 581 KGas constant, R = 8.314 JK−1mol−1According to Arhenious equationK = A e–Ea/RTIn this formula term e–Ea/RTrepresent the number of molecules which have energy equal or more than activation energyNumber of molecules = e–Ea/RTPlug the values we getNumber of molecules |
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