The AG for the reaction,2ZnS(s)+ 302(g)2ZnO(s) + 2S02 (g)will be:(a) 357 kJ(c) -773 kJ(CBSE 2000)(b) - 731 kJ(d) - 229 kJ

The AG for the reaction,2ZnS(s)+ 302(g)2ZnO(s) + 2S02 (g)will be:(a) 3

1.	The AG for the reaction,2ZnS(s)+ 302(g)2ZnO(s) + 2S02 (g)will be:(a) 357 kJ(c) -773 kJ(CBSE 2000)(b) - 731 kJ(d) - 229 kJ
Answer» ENTHALPY OF REACTION[2ΔHf(ZnO (s)) + 2ΔHf(SO2 (g))] - [2ΔHf(ZnS (s sphalerite)) + 3ΔHf(O2 (g))][2(-348.28) + 2(-296.83)] - [2(-205.98) + 3(0)] = -878.26 kJ-878.26 kJ (exothermic)ENTROPY CHANGE[2ΔSf(ZnO (s)) + 2ΔSf(SO2 (g))] - [2ΔSf(ZnS (s sphalerite)) + 3ΔSf(O2 (g))][2(43.64) + 2(248.11)] - [2(57.74) + 3(205.03)] = -147.07 J/K-147.07 J/K (decrease in entropy)FREE ENERGY OF REACTION (AT 298.15 K)From ΔGf° values:[2ΔGf(ZnO (s)) + 2ΔGf(SO2 (g))] - [2ΔGf(ZnS (s sphalerite)) + 3ΔGf(O2 (g))][2(-318.32) + 2(-300.19)] - [2(-201.29) + 3(0)] = -834.44 kJ-834.44 kJ (spontaneous)From ΔG = ΔH - TΔS:-834.41 kJ (spontaneous)