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The Age Of Father 1010 Years Ago Was Thrice The Age Of His Son. Ten Years Hence, Father's Age Will Be Twice That Of His Son. What Is The Ratio Of Their Present Ages? |
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Answer» Let AGE of the SON before 1010 years =x=x and age of the FATHER before 1010 years =3x=3x (3x+20)=2(x+20) Age of the son at present =x+10=20+10=30 Age of the father at present =3x+10=3×20+10=70 Required ratio =70:30=7:3. Let age of the son before 1010 years =x=x and age of the father before 1010 years =3x=3x (3x+20)=2(x+20) Age of the son at present =x+10=20+10=30 Age of the father at present =3x+10=3×20+10=70 Required ratio =70:30=7:3. |
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