The ages of two persons are in the ratio 5: 7. Eighteen years ago thei

1.	The ages of two persons are in the ratio 5: 7. Eighteen years ago their ages were in the ratio 8: 13. Find their present ages.
Answer» Let present ages of two persons be 5x and 7x Given ages of two persons are in the ratio 5: 7 And also given that 18 years ago their ages were in the ratio 8: 13 Therefore (5x – 18)/ (7x – 18) = (8/13) 13 (5x – 18) = 8 (7x – 18) 65x – 234 = 56x – 144 65x – 56x = 234 – 144 9x = 90 x = 90/9 x = 10 Thus the ages are 5x = 5 (10) = 50 years And 7x = 7 (10) = 70 years

The ages of two persons are in the ratio 5: 7. Eighteen years ago their ages were in the ratio 8: 13. Find their present ages.

Answer»

Let present ages of two persons be 5x and 7x

Given ages of two persons are in the ratio 5: 7

And also given that 18 years ago their ages were in the ratio 8: 13

Therefore (5x – 18)/ (7x – 18) = (8/13)

13 (5x – 18) = 8 (7x – 18)

65x – 234 = 56x – 144

65x – 56x = 234 – 144

9x = 90

x = 90/9

x = 10

Thus the ages are 5x = 5 (10) = 50 years

And 7x = 7 (10) = 70 years