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    				| 1. | The algebraic form for the sum of first n terms of an arithmetic sequence is 2n2 + 8n. How many consecutive terms of the sequence from the first, are to be added to get 330 ? | 
| Answer» Sn = 2n2 + 8n (Given) 330 = 2n2 + 8n 2n2 + 8n – 330 = 0 n2 + 4n – 165 = 0 n2 + 15n – 11n – 165 = 0 n(n + 15) – 11 (n + 15) = 0 (n + 15) (n – 11) = 0 If n + 15 = 0 ⇒ n = – 15 (terms are not negative) n – 11 = 0 ⇒ n = 11 ∴ Hence, total 11 term from starting to be added. | |