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    				| 1. | The alkene that axhibits geometrical isomerism isA. but`-2-`eneB. propeneC. `2-`methy`1`but`-2`-eneD. `2-`methy`1`propene | 
| Answer» Correct Answer - A `{:(underset(But-2-en e)(CH_(3)CH=CHCH_(3)),,underset(Prpen e)(CH_(3)CH=CH_(2)),,),(underset(2-Methy1but-2-en e)((CH_(3))_(2)C=CHCH_(3)),,underset(2-Methy1pr open e)((CH_(3))_(2)C=CH_(2)),,):}` Alkenes with two identical ligands on the same double-bonded `C` have no geometric isomers. only in but`-2-`ene each doubly-bonded carbon has two different ligands | |