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The amgular velocity and the amplitude of a simple pendulum is `omega` and a respectively. At a displacement x from the mean position, if its kinetic energy is T and potential energy is U, then the ratio of T to U isA. `((a^(2)-x^(2) omega^(2))/(x^(2)omega^(2)))`B. `(x^(2)omega^(2))/((a^(2)-x^(2)omega^(2)))`C. `((a^(2)-x^(2)))/(x^(2))`D. `(x^(2))/((a^(2)-x^(2)))` |
Answer» Correct Answer - C |
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