The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is :

The ammonia evolved from the treatment of 0.30 g of an organic compoun

1.	The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid. The excess of acid required 20 mL of 0.5 M sodium hydroxide solution for complete neutralization. The organic compound is :
Answer» acetamide benzamide urea thiourea Solution :`H_(2)SO_(4)+2KOH to K_(2)SO_(4)+2H_(2)O` `(M_(1)V_(1))/(1) ("excess" H_(2)SO_(4))=(M_(2)V_(2))/(2)(KOH)` `(0.1xxV_(1))/(1)=(0.5xx20)/(2)` `V_(1)=50 mL` Volume of sulphuric acid USED up to absorb `NH_(3)=50 mL` `% N=(2.8xxMV)/(W)=(2.8xx0.1xx50)/(0.3)=46.6` Thus, the organic compound will be urea, which has 46.6% nitrogen.