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The amount of anhydrous `Na_(2)CO_(3)` present in 250 ml of 0.25 M solution isA. 6.225 gB. 66.25 gC. 6.0 gD. 6.625 g |
Answer» Correct Answer - D `M=(w)/(m xxV(l)) , 0.25 = (w)/(106xx0.25), w=6.625 gm` |
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