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The amount of energy released when 1 x 1010 atoms of chlorine in vapour state are converted to Cl- ions according to the equation.Cl(g) + e- → Cl- (g) is 57.86 × 10-10 JCalculate the electron gain enthalpy of chlorine atom in terms of kJ mol-1 and eV per atom. |
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Answer» Given CI(g) + e− → CI− (g) is 57.86 × 10−10J (1 x 1010 atom) \(\therefore\) Electron gain enthalpy of chlorine i.e. the amount of energy released when 1 mole (6.023 x 1023) atoms of chlorine are converted into CI- ions according to the above equation will be = \(\frac{57.86\times10^{-10}}{1\times10^{10}}\) x 6.023 x 1023 = -348.49 x 103 J mol-1 = -348.49 kJ mol-1 . 1 eV/atom = 96.49 kJ mol-1 Electron gain enthalpy of chlorine = -\(\frac{348.49}{96.49}\) = -3.61 eV/atom |
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