The amount of heat evolved when 500 cm^3 of 0.1 M HCl is mixed with 20

1.	The amount of heat evolved when 500 cm^3 of 0.1 M HCl is mixed with 200 cm^3 of0.2 M NaOH is1) 1.292 kJ2) 2.292 kJ3) 3.392 kJ4) 0.292 kJ(with method please)
Answer» hyy mate ✌️ 500cm3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions. 200CM3 of 0.2 M NAOH corresponds to 0.2×0.2=0.04 moles of hydroxide ions. The ENTHALPY of NEUTRALISATION is 57.3 kJ/mol. hope you are not the intended recipient

The amount of heat evolved when 500 cm^3 of 0.1 M HCl is mixed with 200 cm^3 of0.2 M NaOH is1) 1.292 kJ2) 2.292 kJ3) 3.392 kJ4) 0.292 kJ(with method please)

Answer»

hyy mate ✌️

500cm3 of 0.1 M HCl corresponds to 0.5×0.1=0.05 moles of hydrogen ions. 200CM3 of 0.2 M NAOH corresponds to 0.2×0.2=0.04 moles of hydroxide ions. The ENTHALPY of NEUTRALISATION is 57.3 kJ/mol.

hope you are not the intended recipient

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The amount of heat evolved when 500 cm^3 of 0.1 M HCl is mixed with 200 cm^3 of0.2 M NaOH is1) 1.292 kJ2) 2.292 kJ3) 3.392 kJ4) 0.292 kJ(with method please)​

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The amount of heat evolved when 500 cm^3 of 0.1 M HCl is mixed with 200 cm^3 of0.2 M NaOH is1) 1.292 kJ2) 2.292 kJ3) 3.392 kJ4) 0.292 kJ(with method please)