The amount of heat evolved when 500cm^(3) of0.1 MHCl is mixed with 200

1.	The amount of heat evolved when 500cm^(3) of0.1 MHCl is mixed with 200 cm^(3) of 0.2 M NaOH is "….................."
Answer» 2.292 Kj 1.292 kJ `0.292kJ` `3. 292 kJ` SOLUTION :`500 CM^(3)` of 0.1 HCl `=500 xx0.1` millimole `=50` millimole`=0.050`mole `200 cm^(3)` of0.2 M NaOH `= 200 xx0.2` millimole `=4` millimole `=40`millimole `=0.040 ` mole Thus, 0.04 mole of NaOH neturalizes 0.04 mole of HCl. Heat evolved from 1 mole of HCl`= 57.3 kJ` `:.` Heat evolved from0.04mole of HCl `= 57.3xx 0.04 kJ=2.292kJ`

Discussion