The amount of heat required to convert 5 g of ice at 0∘C to 5 g of steam at 100∘C is -[Latent heat of vaporization and fusion are Lv=540 cal g−1 and Lf=80 cal g−1]

The amount of heat required to convert 5 g of ice at 0∘C to 5 g of s

1.	The amount of heat required to convert 5 g of ice at 0∘C to 5 g of steam at 100∘C is -[Latent heat of vaporization and fusion are Lv=540 cal g−1 and Lf=80 cal g−1]
Answer» The amount of heat required to convert $5 g$ of ice at $0^{\circ} C$ to $5 g$ of steam at $100^{\circ} C$ is - [Latent heat of vaporization and fusion are $L_{v} = 540 {cal g}^{- 1}$ and $L_{f} = 80 {cal g}^{- 1}$ ]

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The amount of heat required to convert 5 g of ice at 0∘C to 5 g of steam at 100∘C is -[Latent heat of vaporization and fusion are Lv=540 cal g−1 and Lf=80 cal g−1]

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