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The amount of water that should be added to 500 ml of 0.5 N solution of NaOH to give a concentration of 10 mg per ml isA. (a)100B. (b)200C. (c )250D. (d)500 |
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Answer» Correct Answer - D `N_(1)=0.5 N rarr 10 g per ml` `N_(2)=(10xx10^(-3)g)/(40xx1)xx1000=0.25 N` `V_(1)=500 ml, V_(2)=?` `N_(1)V_(1)=N_(2)V_(2), 0.5xx500=0.25xxV_(2)` `V_(2)=1000 ml` final volume water added`=1000-500=500 mL`. |
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