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The amplitude and periodic time of SHM are 5 cm and 6 s, respectively. What is the phase at a distance of 2.5 cm from the mean position? |
Answer» Data : A = 5 cm, T = 6 s, x = 2.5 cm Since the particle starts from the mean position, its epoch, α = 0. ∴ The equation of motion is x = A sin ωt ∴ The required phase of the particle, ω = sin-1 \(\frac xA\) = sin-1 \(\frac{2.5}5\) = sin-1 \(\frac 12\) = \(\frac {\pi}6\) rad |
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