The amplitude and time period of a simple pendulum bob are 0.05m and 2 s respectively. Then the maximum velocity of the bob is :

The amplitude and time period of a simple pendulum bob are 0.05m and 2

1.	The amplitude and time period of a simple pendulum bob are 0.05m and 2 s respectively. Then the maximum velocity of the bob is :
Answer» `0.157 ms^(-1)` `0.257 ms^(-1)` `0.10 ms^(-1)` `0.025 ms^(-1)` Solution :`V_(rms) = a OMEGA = a ((2pi)/(T))` ` = 0.05 ((2pi)/(2) ) =0.05 XX 3.14 ` ` V_(rms) = 0.157 ms^(-1)`