1.

The amplitude of a damped oscillator becomes half in one minute. The amplitude after three minutes will be (1)/(x) times the original, then find the value of x.

Answer»

`2XX 3`
`2^3`
`3^2`
`3 xx 2^(2)`

Solution :Amplitude of damped OSCILLATION at time t,
`A(t) = A_(0)e^(-(bt)/(2m))`
After `t= 1 MIN, A(2) = (A_0)/(2)`
`therefore (A_0)/(2) = A_(0)e^(-(b(1))/(2m))`
`therefore (1)/(2)= e^(-(b)/(2m))`
`therefore 2 = e^(-(b)/(2m))"""........."(1)`
Now, after `t= 3 min, A(3) = (A_0)/(x)`
`therefore (A_0)/(x) = A_(0)e^(-(b(3))/(2m))`
`therefore (1)/(x)= e^(-(3b)/(2m))`
`therefore x = e^((3b)/(2m))= (e^((b)/(2m)))^(3)`
`therefore x= 2^(3)` (from equation (1)).


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