The amplitude of vibration of a particle is given by `a_m=(a_0)//(aomega^2-bomega+c)`, where `a_0`, a, b and c are positive. The condition for a single resonant frequency isA. `b^2=4ac`B. `b^2gt4ac`C. `b^2=5ac`D. `b^2=7ac`

The amplitude of vibration of a particle is given by `a_m=(a_0)//(aome

1.	The amplitude of vibration of a particle is given by `a_m=(a_0)//(aomega^2-bomega+c)`, where `a_0`, a, b and c are positive. The condition for a single resonant frequency isA. `b^2=4ac`B. `b^2gt4ac`C. `b^2=5ac`D. `b^2=7ac`
Answer» Correct Answer - A `aomega^2-bomega+c=0impliesomega=(b+-sqrt(b^2-4ac))/(2a)` For single frequency `b^2=4ac`

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The amplitude of vibration of a particle is given by `a_m=(a_0)//(aomega^2-bomega+c)`, where `a_0`, a, b and c are positive. The condition for a single resonant frequency isA. `b^2=4ac`B. `b^2gt4ac`C. `b^2=5ac`D. `b^2=7ac`

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