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The angle between force vecF =(3hati+4hatj-5hatk) unit and displacement vecd = (5hati+4hatj+3hatk) unit is |
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Answer» `cos^(-1) (0.16)` `vecd=5hati+4hatj+3hatk` unit `therefore |vecF|=sqrt((3)^2 +(4)^2 + (-5)^(2))=sqrt50` unit `|vecd|=sqrt((5)^2+(4)^2+(3)^2)=sqrt50` unit Let `theta` be angle between `vecF` and `vecd` `therefore cos theta=(vecF.vecd)/(|vecF||vecd|)=((3hati+4hatj-5hatk).(5hati+4hatj+3hatk))/(sqrt50sqrt50)` `=(15+16-15)/50=16/50 =0.32 "or" theta=cos^(-1) (0.32)` |
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