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InterviewSolution
| 1. |
The angle between force vecF =(3hati+4hatj-5hatk) unit and displacement vecd = (5hati+4hatj+3hatk) unit is |
| Answer» <html><body><p>`cos^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>) (0.16)`<br/>`cos^(-1) (0.32)`<br/>`cos^(-1) (0.24)`<br/>`cos^(-1) (0.64)`</p>Solution :Here, `<a href="https://interviewquestions.tuteehub.com/tag/vecf-3257300" style="font-weight:bold;" target="_blank" title="Click to know more about VECF">VECF</a>=3hati+4hatj-5hatk` unit <br/> `vecd=5hati+4hatj+3hatk` unit <br/> `therefore |vecF|=sqrt((<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)^<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> +(4)^2 + (-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>)^(2))=sqrt50` unit <br/> `|vecd|=sqrt((5)^2+(4)^2+(3)^2)=sqrt50` unit<br/> Let `theta` be angle between `vecF` and `vecd` <br/> `therefore cos theta=(vecF.vecd)/(|vecF||vecd|)=((3hati+4hatj-5hatk).(5hati+4hatj+3hatk))/(sqrt50sqrt50)` <br/> `=(15+16-15)/50=16/50 =0.32 "or" theta=cos^(-1) (0.32)`</body></html> | |