1.

The angle between the tangents drawn from the point (-a, 2a) to `y^2`=4ax is

Answer» `y^2=4ax`
`y=mx+a/m`
`2a=-ma+a/m`
`2=(-m+1)/m`
`m^2+2m-1=0`
`tantheta=|(m_1-m_2)/(1+m_1m_2)|`
`tanttheta=1/0=oo`
`theta=pi/2`.


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