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The angle between the vector `-hati+hatj` and `2hati+3hatj` is :A. `cos theta=(4)/(6)`B. `sin theta=sqrt((25)/(26))`C. `tan theta=sqrt(5)`D. none of these |
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Answer» `cos theta=(veca,vecb)/(ab)=(2+3)/sqrt(2)sqrt(13)=(1)/sqrt(26)` `sin theta=sqrt((25)/(26))` |
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