Saved Bookmarks
| 1. |
The angle between vectors `(hati+hatj)` and `(hatj+hatk)` is :A. `90^(@)`B. `180^(@)`C. `0^(@)`D. `60^(@)` |
|
Answer» Correct Answer - D `cos theta=(vecA.vecB)/(AB)=((hati+hatj).(hatj+hatk))/(sqrt(2),sqrt(2))=(1)/(2)rArr theta=60^(@)` |
|