1.

The angle between vectors `(hati+hatj)` and `(hatj+hatk)` is :A. `90^(@)`B. `180^(@)`C. `0^(@)`D. `60^(@)`

Answer» Correct Answer - D
`cos theta=(vecA.vecB)/(AB)=((hati+hatj).(hatj+hatk))/(sqrt(2),sqrt(2))=(1)/(2)rArr theta=60^(@)`


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