1.

The angle of dip at a certain place on Earth is 30^o and the magnitude of Earth’s horizontal component of magnetic field is 0.35 G. Find the magnetic field at that place on Earth.(a) 0.35 G(b) 0.40 G(c) 0.45 G(d) 0.50 GThe question was asked during an online interview.My question is from Earth’s Magnetism topic in chapter Magnetism and Matter of Physics – Class 12

Answer»

Right choice is (b) 0.40 G

The best explanation: GIVEN: Horizontal COMPONENT (H) = 0.35 G; ANGLE of dip (δ) = 30^o

Required equation ➔ cosδ=\(\frac {H}{B}\)

B=\(\frac {H}{cos\delta } = \frac {0.35}{cos30^o} = \frac {0.35}{\frac {\sqrt {3}}{2}} =\frac {0.35\times 2}{1.732}\)=0.40

Therefore, the MAGNITUDE of the magnetic field at that PLACE is 0.40 G.


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