1.

The angle of dip at place is delta. If dip is measured in a plane making an angle theta with the magnetic meridian, the apparent angle of dip delta_(1) will be equal to

Answer»

`tan_(-1) (tan delta SEC THETA)`
`tan^(-1)(tan delta sin theta)`
`tan^(-1) (tan theta costheta)`
`tan^(-1) (tandelta COSEC theta)`

SOLUTION :`tan delta = "vertical COMPONENT"/"Horizontal component"=V/H`
Again, `tandelta_(1) = V/(H. cos theta) = (tandelta)/(cos that)=tan delta sec theta`
`implies delta_(1) = tan^(-1) (tantheta sec theta)`


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