InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
The angle of incidence for a ray of light at a refracting surface of a prism is `45^(@)`. The angle of prism is `60^(@)`. If the ray suffers minimum deviation through the prism, the angle of minimum deviation and refractive index of the material of the prism respectively, are `:`A. `30^@, sqrt(2)`B. `45^@, sqrt(2)`C. `30^@, (1)/(sqrt(2))`D. `45^@, (1)/(sqrt(2))` |
|
Answer» Correct Answer - A Here, `i_1 = 45^@, A = 60^@ , delta_m = ? Mu = ?` When the ray suffers minimum deviation, `i_1 = i_2. As A + delta_m i_1 + i_2 = 90^@` `delta_m = 90^@ - A = 90^@ - 60^@ = 30^@` `mu = (sin(A + delta_m)//2)/(sin A//2) = (sin(60^@ + 30^@)//2)/(sin 60^@//2)` =`(sin 45^@)/(sin 30^@) = (1//sqrt(2))/(1//2) = sqrt(2)`. |
|