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The angle of inclination of an inclined plane is `60^(@)`. Coefficient of friction between `10kg` body on it and its surface is `0.2, g= 10ms^(-2)`. The acceleration of the body down the plane in `ms^(-2)` is .A. `5.667`B. `6.66`C. `7.66`D. Zero |
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Answer» Correct Answer - C `F =ma, a = g (sin theta -mu_(k) cos theta)` |
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