The angle turned by a body undergoing circular motion depends on time as `theta=theta_(0)+theta_(1) t+theta_(2)r^(2)`. Then the angular acceleration of the body isA. `theta_(1)`B. `theta_(2)`C. `2theta_(1)`D. `2theta_(2)`

The angle turned by a body undergoing circular motion depends on time

1.	The angle turned by a body undergoing circular motion depends on time as `theta=theta_(0)+theta_(1) t+theta_(2)r^(2)`. Then the angular acceleration of the body isA. `theta_(1)`B. `theta_(2)`C. `2theta_(1)`D. `2theta_(2)`
Answer» `theta=theta_(0)+theta_(1) t+theta_(2) t^(2), omega=(d theta)/(dt)=theta_(1)+2theta_(2)t` `alpha=(d omega)/(dt)=2theta_(2)`

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The angle turned by a body undergoing circular motion depends on time as `theta=theta_(0)+theta_(1) t+theta_(2)r^(2)`. Then the angular acceleration of the body isA. `theta_(1)`B. `theta_(2)`C. `2theta_(1)`D. `2theta_(2)`

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