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The angles of a triangle are (x + 10)°, (x – 20)° and (x + 40)°. Find the value of x and the measure of the angles. |
Answer» Given that the angles of the triangle are (x + 10)°, (x – 20)° and (x + 40)° (x + 10)° + (x – 20)° + (x + 40)° = 180° ⇒ x + 10° + x – 20° + x + 40° = 180° ⇒ 3x + 30° = 180° ⇒ 3x – 180° – 30° ⇒ 3x = 150° ⇒ x = 150°/3 = 50° The angles are, x + 10° = 50° + 10° = 60° x – 20° = 50° – 20° = 30° x + 40° = 50° + 40° = 90° ∴ Measure of the angles are 60°, 30° and 90°. |
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