The angles of a triangle are (x − 40)°, (x − 20)° and (1/2 x �

1.	The angles of a triangle are (x − 40)°, (x − 20)° and (1/2 x − 10)°. Find the value of x.
Answer» The angles of a triangle are (x − 40)°, (x − 20)° and (1/2 x − 10)° Sum of all angles of triangle = 180° (x − 40)° + (x − 20)° + (1/2 x − 10)° = 180° 5/2 x – 70° = 180° 5/2 x = 180° + 70° 5x = 2(250)° x = 500/5 x = 100°

The angles of a triangle are (x − 40)°, (x − 20)° and (1/2 x − 10)°. Find the value of x.

Answer»

The angles of a triangle are (x − 40)°, (x − 20)° and (1/2 x − 10)°

Sum of all angles of triangle = 180°

(x − 40)° + (x − 20)° + (1/2 x − 10)° = 180°

5/2 x – 70° = 180°

5/2 x = 180° + 70°

5x = 2(250)°

x = 500/5

x = 100°