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The angles of elevation of the top of a tower the base and the top of a building are 60° and 30°. 3x + 5y ≤ 15, 5x + 2y ≤ 10 and x ≥ 0, y ≥ 0. |
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Answer» Let AB = Building & CD is the tower. From the rt angled ∆ ACD We have tan 60 = \(\frac{h}{x}\) √3 = \(\frac{h}{x}\) ⇒ x = √3(h -20) From 1 and 2 wet √3(h – 20) = \(\frac{h}{\sqrt 3}\) ⇒ 3(h – 20) = h ⇒ 3h – 60 = h ⇒ 3h – 60 = h ⇒ 2h = 60 ⇒ h = 30 mts ∴ Height of the tower = 30 mts |
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