1.

The angular displacement at any time t is given by `theta(t) = 2t^(3)-6^(2)`. The torque on the wheel will be zero atA. 1 sB. 0.1 sC. 2 sD. 0.2s

Answer» a) Given, `theta`(t) = 2t^(2)-6t^(2) rArr (dtheta)/(dt) = 6t^(2)-12t`
`d^(2)theta)/(dt^(2)` = 12t -12
For torque, `rho = Ialpha`=0
`(d^(2)theta))/(dt^(2))` =0 rArr 12t^(2)-12 =0
`therefore` t=1s


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