InterviewSolution
Saved Bookmarks
| 1. |
The angular displacement at any time t is given by `theta(t) = 2t^(3)-6^(2)`. The torque on the wheel will be zero atA. 1 sB. 0.1 sC. 2 sD. 0.2s |
|
Answer» a) Given, `theta`(t) = 2t^(2)-6t^(2) rArr (dtheta)/(dt) = 6t^(2)-12t` `d^(2)theta)/(dt^(2)` = 12t -12 For torque, `rho = Ialpha`=0 `(d^(2)theta))/(dt^(2))` =0 rArr 12t^(2)-12 =0 `therefore` t=1s |
|