1.

The angular frequency of the damped oscillator is given by, omega = sqrt(((k)/(m)-(b^(2))/(4m^(2)))where k is the spring constant, m is the mass of the oscillatory and b is the damping constant. If the ratio (b^(2))/(mk) is 8%, the change in time period compared to the undamped oscillator is approximately as follows:

Answer»

INCREASES by 1%
increases by 8%
DECREASES by 1%
decreases by 8%

ANSWER :A


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