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The angular momentum (M) of a particle relative to a certain point (O), varies with time as vec(M)=vec(a)+vec(b)t^(2) where vec(a) and vec(b) are constant vectors and vec(a) is perpendicular to vec(b). The moment of the force (N) relative to the point O, acting on the particle, when N makes 45^(@) with M is xbsqrt(a//b). Find the value of x ? |
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a></body></html> | |