The angular momentum of a body changes by 80kg m^(2)s^(-1) when its angular velocity changes from 20 rad s^(-1) to 40 rad s^(-1). Find the change in its kinetic energy of rotation.

The angular momentum of a body changes by 80kg m^(2)s^(-1) when its an

1.	The angular momentum of a body changes by 80kg m^(2)s^(-1) when its angular velocity changes from 20 rad s^(-1) to 40 rad s^(-1). Find the change in its kinetic energy of rotation.
Answer» <html><body><p></p>Solution :Change in angular momentum of the body <br/> `L_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)-L_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)=I(omega_(2)-omega_(1))` <br/> Change in <a href="https://interviewquestions.tuteehub.com/tag/kinetic-533291" style="font-weight:bold;" target="_blank" title="Click to know more about KINETIC">KINETIC</a> energy `=(1)/(2)<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a>(omega_(2)^(2)-omega_(1)^(2))` <br/> `("change in K.E")/("change in angular momentum")=(omega_(2)+omega_(1))/(2)` <br/> `:.` change in K.E. `=80((20+40)/(2))=2400J`</body></html>