1.

The angular momentum of rotating body is increased by 20%. What will be the increase in its rotational kinetic energy ?

Answer»

SOLUTION :Kinetic energy K.E. `= (L^(2))/(2I) "" E alpha L^(2)`
`(E+Delta E)/(E )=((120)/(100))^(2)`(or) `(Delta E)/(E )=0.44` (or) `(Delta E)/(E ) xx100 =44%`


Discussion

No Comment Found