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The angular momentum of rotating body is increased by 20%. What will be the increase in its rotational kinetic energy ? |
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Answer» SOLUTION :Kinetic energy K.E. `= (L^(2))/(2I) "" E alpha L^(2)` `(E+Delta E)/(E )=((120)/(100))^(2)`(or) `(Delta E)/(E )=0.44` (or) `(Delta E)/(E ) xx100 =44%` |
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