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The angular momentum of rotating body is increased by 20 %. What will be the increase in its rotational kinetic energy ? |
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Answer» SOLUTION :KINETIC energy K.E. `=(L^(2))/(2I)""EalphaL^(2)` `(E+DeltaE)/(E)=((120)/(100))^(2)` (or) `(DeltaE)/(E)=0.44` `(DeltaE)/(E)xx100=44%` |
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