The angular speed of hour hand of a watch is …………. rad s^(-1).

1.	The angular speed of hour hand of a watch is …………. rad s^(-1).
Answer» `(pi)/(43200)` `(pi)/(1800)` `(pi)/(30)` `(pi)/(21600)` SOLUTION :`omega=(2pi)/(T)=(2pi)/(12xx3600)=(pi)/(21600)" RAD s"^(-1)`

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