1.

The angular speed of hour hand of a watch is …………. rad s^(-1).

Answer»

`(pi)/(43200)`
`(pi)/(1800)`
`(pi)/(30)`
`(pi)/(21600)`

SOLUTION :`omega=(2pi)/(T)=(2pi)/(12xx3600)=(pi)/(21600)" RAD s"^(-1)`


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