The angular velocity and the amplitude of a simple pendulum is omega and A respectively. At a displacement x from the mean position if its kinetic energy is k and potential energy U, then the ratio of K and U is………..

The angular velocity and the amplitude of a simple pendulum is omega a

1.	The angular velocity and the amplitude of a simple pendulum is omega and A respectively. At a displacement x from the mean position if its kinetic energy is k and potential energy U, then the ratio of K and U is………..
Answer» `(x^(2) omega^(2))/((A^(2)-x^(2)omega^(2))` `(x^(2))/((A^(2)-x^(2))` `(A^(2)-x^(2)omega^(2))/(x^(2) omega^(2))` `(A^(2)-x^(2))/(x^(2))` SOLUTION :Kinetic ENERGY `K= (1)/(2) m omega^(2) (A^(2)-x^(2))` and potential energy `U= (1)/(2) m omega^(2) x^(2)` `THEREFORE (K)/(U)= (A^(2)-x^(2))/(x^2)`.