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The anti-derivative of `sin 2x-4e^(3x)` isA. `(1)/(2)cos 2x-(4)/(3)e^(3x)+C`B. `-(1)/(2)cos 2x+(4)/(3)e^(3x)+C`C. `-(1)/(2)cos 2x-(4)/(3)e^(3x)+C`D. None of these |
Answer» Correct Answer - C We have, `int(sin 2x-4e^(3x))dx` `=intsin 2xdx-4inte^(3x)dx` `=(-cos2x)/(2)-4e^(3x)dx` `=(-cos2x)/(2)-4(e^(3x))/(3)+C` `=-(1)/(2)cos2x-(4)/(3)e^(3x)+C` |
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