1.

The apparatus shown consists of three bulbs connected by stopcocks of negligible volume . The temperature is constant . P_(A) = 2.13atm "" P_(B) = 0.861 atm P_(C) = 1.15 atm "" V_(A) = 1.50 L V_(B) = 1.0 L "" V_(C) = 2.0 L When all the stopcocks are opened , the pressure in the bulb 'B' will be

Answer»

<P>1.41 ATM
0.861 atm
1.38 at m
1.18 atm

Solution :`P = (2.13 xx 1.5 xx 0.86 xx 1 + 1 .15 xx 2)/(4.5)`
= 1.41 atm


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