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The apparent corfficient of expansion of a liquid when heated, filled in vessel A and B of identical volumes, is found to be `gamma_1` and `gamma_2`, respectively. If `alpha_1` be the linear expansivity of A then that of B will beA. `((gamma_1-gamma_2))/(3)-alpha_1`B. `((gamma_2-gamma_1))/(3)+alpha_1`C. `((gamma_2-gamma_1))/(3)-alpha_1`D. `((gamma_1-gamma_2))/(3)+alpha_1` |
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Answer» Correct Answer - B Let V be the volume of the liquid and `DeltaT` the rise in temperature Since apparent expansion`=`true expansion`-`expansion of vessel `Vgamma_1DeltaT=VgammaDeltaT+V(3alpha_1)DeltaT` or `gamma_1=gamma+3alpha_1` .(i) and `gamma_2=gamma+3alpha_2` .(ii) Where `gamma` is the coefficient of real expansion of the liquid. Substracting Eq. (ii) from Eq. (i) `gamma_1-gamma_2=3(alpha_1-alpha_2)` or `alpha_1-alpha_2=((gamma_1-gamma_2))/(3)` or, `alpha_2=[(gamma_1-gamma_2)//3]+alpha_1` Hence, correct option is (b). |
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