The apparent weight of a man in a lift is w_(1) when lift moves upwards with some acceleration and is w_(2) when it is accelerating down with same acceleration. Find the true weight of the man and acceleration of lift.

The apparent weight of a man in a lift is w_(1) when lift moves upward

1.	The apparent weight of a man in a lift is w_(1) when lift moves upwards with some acceleration and is w_(2) when it is accelerating down with same acceleration. Find the true weight of the man and acceleration of lift.
Answer» Solution :(a) `w_(1)=w(1+(a)/(g)), w_(2)=w(1-(a)/(g))` `w_(1)+w_(2)=2W rArr w=(w_(1)+w_(2))/(2)` (b) `(w_(1))/(w_(2))=(cancel(w)(1+(a)/(g)))/(cancel(w)(1-(a)/(g))) "" (g+a)/(g-a)=(w_(1))/(w_(2))` `(g)/(a)=(w_(1)+w_(2))/(w_(1)-w_(2)) "" a=g((w_(1)-w_(2))/(w_(1)+w_(2)))`