The applied input a.c. power to a half wave retifier I 100 watt. The d – InterviewSolution

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1.	The applied input a.c. power to a half wave retifier I 100 watt. The d.c. output power obtained is 40 watt. (i) What is the rectification efficiency and (ii) What is the power efficiency?
Answer» Rectification efficiency `=(d.c. "output power")/(a.c. "input power")xx100` `40/100xx100=40%` Power efficiency `=(d.c. "output power")/(a.c. "input power for half cycle")` `=40/((100//2))xx100=80%`

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