The approximate production of Na_(2)CO_(3) per month is 424 xx 10^(6) g while that of methyl alcohol is 320xx10^(6) g. Which is produced more in terms of moles?

The approximate production of Na_(2)CO_(3) per month is 424 xx 10^(6)

1.	The approximate production of Na_(2)CO_(3) per month is 424 xx 10^(6) g while that of methyl alcohol is 320xx10^(6) g. Which is produced more in terms of moles?
Answer» SOLUTION :`Na_(2)CO_(3)` mass = `424xx10^(6)` G Molecular mass of `Na_(2)CO_(3)=(23xx2) + 12 + (16xx3)` = 46+ 12 + 48 = 106 g No. of moles of `Na_(2)CO_(3) = (" Mass of" Na_(2)CO_(3))/("Molecular mass of" Na_(2)CO_(3))` =`(424xx10^(6)g)/(106 g)` = `4xx10^(6)` moles Methyl alcohol mass = `320xx10^(6)` g Molecular mass of `CH_(3)OH` = 12 + (1 `xx`4)+ 16 = 32 g = 12 + 4+ 16 = 32 g No. of moles of Methyl alcohol = ` ("Mass of Methyl alcohol")/(" Molecular mass of Methyl alcohol")` `(320xx10^(6)g)/(32 g)` = `10xx10^(6) mol es.` `:.` Methyl alcohol is more produced in TERMS of moles