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The approximate production of Na2CO3 per month is 424 x 106 g while that of methyl alcohol is 320 x 106 g. Which is produced more in terms of moles? |
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Answer» Na2CO3 mass = 424 x 106 g Molecular mass of Na2CO3 = (23 x 2) + 12 + (16 x 3) = 46+ 12 +48 = 106 g No. of moles of Na2 CO3 = (Mass of Na2CO3) / (Molecular mass of Na2CO3) = (424 x 106 g) / 106 g = 4 x 106 moles Methyl alcohol mass = 320 x 106 g Molecular mass of CH3OH = 12 + (1 x 4)+ 16 = 12 + 4 + 16 = 32 g No. of moles of Methyl alcohol = (Mass of Methyl alcohol) / (Molecular mass of Methyl alcohol) = (320 x 106 g) / 32 g = 10 x 106 moles. ∴ Methyl alcohol is more produced in terms of moles. |
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