1.

The approximate production of Na2CO3 per month is 424 x 106 g while that of methyl alcohol is 320 x 106 g. Which is produced more in terms of moles?

Answer»

Na2CO3 mass = 424 x 106

Molecular mass of Na2CO3 

= (23 x 2) + 12 + (16 x 3) 

= 46+ 12 +48 

= 106 g

No. of moles of Na2 CO= (Mass of Na2CO3) / (Molecular mass of Na2CO3)

= (424 x 10g) / 106 g

= 4 x 106 moles 

Methyl alcohol mass = 320 x 106

Molecular mass of CH3OH = 12 + (1 x 4)+ 16 

= 12 + 4 + 16 

= 32 g 

No. of moles of Methyl alcohol = (Mass of Methyl alcohol) / (Molecular mass of Methyl alcohol) 

= (320 x 10g) / 32 g

= 10 x 106 moles. 

∴ Methyl alcohol is more produced in terms of moles.



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