1.

The area bounded between the parabolas `x^2=y/4"and"x^2=9y`and thestraight line `y""=""2`is(1) `20sqrt(2)`(2) `(10sqrt(2))/3`(3) `(20sqrt(2))/3`(4) `10sqrt(2)`

Answer» area of region 1 = area of region 2
area = `int x dy = int y dx`
`| int_0^2 (3 sqrt y - sqrty/2) dy |`
`= 2[ (3y^(3/2))/(3/2) - (y^(3/2))/(3/2 xx2) ]`
`= [(3 xx 2^(3/2) xx 2)/3 - 2^(3/2)/3] = 2 xx 2^(3/2) [2 -1/3]`
`= 2 xx 5/3 xx 2^(3/2) `
`= 10/3xx 2^(3/2) = 20/3sqrt2`
option2 is correct


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