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    				| 1. | The area bounded between the parabolas `x^2=y/4"and"x^2=9y`and thestraight line `y""=""2`is(1) `20sqrt(2)`(2) `(10sqrt(2))/3`(3) `(20sqrt(2))/3`(4) `10sqrt(2)` | 
| Answer» area of region 1 = area of region 2 area = `int x dy = int y dx` `| int_0^2 (3 sqrt y - sqrty/2) dy |` `= 2[ (3y^(3/2))/(3/2) - (y^(3/2))/(3/2 xx2) ]` `= [(3 xx 2^(3/2) xx 2)/3 - 2^(3/2)/3] = 2 xx 2^(3/2) [2 -1/3]` `= 2 xx 5/3 xx 2^(3/2) ` `= 10/3xx 2^(3/2) = 20/3sqrt2` option2 is correct | |