1.

The area enclosed by a circle of diameter 1.06 m to correct number of significant figures is

Answer»

`0.88 m^(2)`
` 0.088 m^(2)`
` 0.882 m^(2)`
`0.530 m^(2)`

Solution :Here `r= (1.06)/(2)= 0.53 m`
`"AREA enclosed" = pir^(2)= 3.14 xx (0.53)^(2)= 0.882026 m^(2) = 0.882 m^(2)` (ROUNDED to THREE significant figures)


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