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The area enclosed by a circle of diameter 1.06 m to correct number of significant figures is |
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Answer» `0.88 m^(2)` `"AREA enclosed" = pir^(2)= 3.14 xx (0.53)^(2)= 0.882026 m^(2) = 0.882 m^(2)` (ROUNDED to THREE significant figures) |
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