The area of a sector of a circle of radius 5 cm is 5π cm2. Find the

1.	The area of a sector of a circle of radius 5 cm is 5π cm2. Find the angle contained by the sector.
Answer» Given, Radius = 5 cm Angle subtended at the centre ‘O’ Area of sector of circle = 5π cm² We know that, Area of the sector = θ/360 ∗ πr² = θ/360 ∗ π5² = 5πθ/72 From the question, we can equate 5π = 5πθ/72 On solving, we have θ = 72° Hence, the angle subtended at the centre of circle is 72°

The area of a sector of a circle of radius 5 cm is 5π cm2. Find the angle contained by the sector.

Answer»

Given,

Radius = 5 cm

Angle subtended at the centre ‘O’

Area of sector of circle = 5π cm²

We know that,

Area of the sector = θ/360 ∗ πr²

= θ/360 ∗ π5²

= 5πθ/72

From the question, we can equate

5π = 5πθ/72

On solving, we have

θ = 72°

Hence, the angle subtended at the centre of circle is 72°